Integrand size = 24, antiderivative size = 27 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {i (a+i a \tan (c+d x))^3}{3 a d} \]
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Time = 0.05 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {3568, 32} \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {i (a+i a \tan (c+d x))^3}{3 a d} \]
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Rule 32
Rule 3568
Rubi steps \begin{align*} \text {integral}& = -\frac {i \text {Subst}\left (\int (a+x)^2 \, dx,x,i a \tan (c+d x)\right )}{a d} \\ & = -\frac {i (a+i a \tan (c+d x))^3}{3 a d} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.85 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {a^2 \tan (c+d x)}{d}+\frac {i a^2 \tan ^2(c+d x)}{d}-\frac {a^2 \tan ^3(c+d x)}{3 d} \]
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Time = 1.97 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.74
method | result | size |
risch | \(\frac {8 i a^{2} \left (3 \,{\mathrm e}^{4 i \left (d x +c \right )}+3 \,{\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}\) | \(47\) |
derivativedivides | \(\frac {-\frac {a^{2} \left (\sin ^{3}\left (d x +c \right )\right )}{3 \cos \left (d x +c \right )^{3}}+\frac {i a^{2}}{\cos \left (d x +c \right )^{2}}+a^{2} \tan \left (d x +c \right )}{d}\) | \(51\) |
default | \(\frac {-\frac {a^{2} \left (\sin ^{3}\left (d x +c \right )\right )}{3 \cos \left (d x +c \right )^{3}}+\frac {i a^{2}}{\cos \left (d x +c \right )^{2}}+a^{2} \tan \left (d x +c \right )}{d}\) | \(51\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 75 vs. \(2 (21) = 42\).
Time = 0.23 (sec) , antiderivative size = 75, normalized size of antiderivative = 2.78 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {8 \, {\left (-3 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} - 3 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - i \, a^{2}\right )}}{3 \, {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} + 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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\[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=- a^{2} \left (\int \tan ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx + \int \left (- 2 i \tan {\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\right )\, dx + \int \left (- \sec ^{2}{\left (c + d x \right )}\right )\, dx\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.78 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {i \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3}}{3 \, a d} \]
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none
Time = 0.46 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.56 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=-\frac {a^{2} \tan \left (d x + c\right )^{3} - 3 i \, a^{2} \tan \left (d x + c\right )^{2} - 3 \, a^{2} \tan \left (d x + c\right )}{3 \, d} \]
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Time = 4.06 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.30 \[ \int \sec ^2(c+d x) (a+i a \tan (c+d x))^2 \, dx=\frac {a^2\,\mathrm {tan}\left (c+d\,x\right )\,\left (-{\mathrm {tan}\left (c+d\,x\right )}^2+\mathrm {tan}\left (c+d\,x\right )\,3{}\mathrm {i}+3\right )}{3\,d} \]
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